Ch\u01a1i k\u00e8o t\u00e0i x\u1ec9u hi\u1ec7p 2 khi hi\u1ec7p 1 k\u1ebft qu\u1ea3 0:0<\/figcaption><\/figure>\nN\u1ebfu khi hi\u1ec7p 2 b\u1eaft \u0111\u1ea7u m\u00e0 t\u1ef7 l\u1ec7 T\u00e0i x\u1ec9u l\u00e0 1.0 hay 1.25. Sau \u0111\u00f3 b\u1ea1n th\u1ea5y t\u1ef7 s\u1ed1 n\u00e0y b\u1ecb r\u01a1i xu\u1ed1ng \u0111i\u1ec3m d\u01b0\u1edbi 1 th\u00ec b\u1ea1n h\u00e3y \u0111\u00e1nh cho c\u1eeda T\u00e0i. Ng\u01b0\u1eddi ch\u01a1i ch\u1ec9 n\u00ean xu\u1ed1ng ti\u1ec1n cho c\u1eeda T\u00e0i khi tr\u1eadn \u0111\u1ea5u thi \u0111\u1ea5u \u1edf ph\u00fat th\u1ee9 58 tr\u1edf \u0111i.<\/p>\n
\u0110\u00e1nh k\u00e8o T\u00e0i x\u1ec9u d\u1ef1a v\u00e0o l\u1ed1i ch\u01a1i c\u1ee7a 2 \u0111\u1ed9i<\/h3>\n
L\u1ed1i ch\u01a1i c\u1ee7a 2 \u0111\u1ed9i quy\u1ebft \u0111\u1ecbnh nhi\u1ec1u \u0111\u1ebfn vi\u1ec7c tr\u1eadn \u0111\u1ea5u s\u1ebd c\u00f3 \u00edt hay nhi\u1ec1u b\u00e0n th\u1eafng \u0111\u01b0\u1ee3c ghi. C\u1ee5 th\u1ec3 l\u00e0:<\/p>\n