C\u00e1c h\u00ecnh th\u1ee9c \u0111\u00e1nh L\u00f4 xi\u00ean \u2013 l\u00f4 \u0111\u00e1 \u0111a d\u1ea1ng<\/figcaption><\/figure>\n\u0110\u00e1nh xi\u00ean 2<\/h3>\n
Ng\u01b0\u1eddi ch\u01a1i s\u1ebd l\u1ef1a ch\u1ecdn 2 con s\u1ed1 n\u1eb1m trong 00 – 99 \u0111\u1ec3 \u0111\u00e1nh trong ng\u00e0y. N\u1ebfu c\u1ea3 2 con s\u1ed1 n\u00e0y c\u00f9ng xu\u1ea5t hi\u1ec7n tr\u00ean b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc th\u00ec b\u1ea1n th\u1eafng. Ng\u01b0\u1ee3c l\u1ea1i n\u1ebfu c\u00f3 duy nh\u1ea5t 1 con s\u1ed1 kh\u00f4ng v\u1ec1 th\u00f4i th\u00ec b\u1ea1n c\u0169ng \u0111\u00e3 b\u1ecb t\u00ednh l\u00e0 thua cu\u1ed9c. V\u1edbi t\u1ef7 l\u1ec7 \u0103n th\u01b0\u1edfng l\u00e0 1:16.5 (Nh\u00e0 \u0111\u00e0i mi\u1ec1n B\u1eafc) v\u00e0 1:27.5 (Nh\u00e0 \u0111\u00e0i mi\u1ec1n Trung – Nam).<\/p>\n
\u0110\u00e1nh xi\u00ean 3<\/h3>\n
Ng\u01b0\u1eddi ch\u01a1i s\u1ebd l\u1ef1a ch\u1ecdn 3 con s\u1ed1 n\u1eb1m trong 00 – 99 \u0111\u1ec3 \u0111\u00e1nh trong ng\u00e0y. N\u1ebfu c\u1ea3 3 con s\u1ed1 n\u00e0y c\u00f9ng xu\u1ea5t hi\u1ec7n tr\u00ean b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc th\u00ec b\u1ea1n th\u1eafng. Ng\u01b0\u1ee3c l\u1ea1i n\u1ebfu c\u00f3 duy nh\u1ea5t 1 con s\u1ed1 kh\u00f4ng v\u1ec1 th\u00f4i th\u00ec b\u1ea1n c\u0169ng \u0111\u00e3 b\u1ecb t\u00ednh l\u00e0 thua cu\u1ed9c. V\u1edbi t\u1ef7 l\u1ec7 \u0103n th\u01b0\u1edfng l\u00e0 1:65 (Nh\u00e0 \u0111\u00e0i mi\u1ec1n B\u1eafc) v\u00e0 1:135 (Nh\u00e0 \u0111\u00e0i mi\u1ec1n Trung – Nam).<\/p>\n
\u0110\u00e1nh xi\u00ean 4<\/h3>\n
Ng\u01b0\u1eddi ch\u01a1i s\u1ebd l\u1ef1a ch\u1ecdn 4 con s\u1ed1 n\u1eb1m trong 00 – 99 \u0111\u1ec3 \u0111\u00e1nh trong ng\u00e0y. N\u1ebfu c\u1ea3 4 con s\u1ed1 n\u00e0y c\u00f9ng xu\u1ea5t hi\u1ec7n tr\u00ean b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc th\u00ec b\u1ea1n th\u1eafng. Ng\u01b0\u1ee3c l\u1ea1i n\u1ebfu c\u00f3 duy nh\u1ea5t 1 con s\u1ed1 kh\u00f4ng v\u1ec1 th\u00f4i th\u00ec b\u1ea1n c\u0169ng \u0111\u00e3 b\u1ecb t\u00ednh l\u00e0 thua cu\u1ed9c. V\u1edbi t\u1ef7 l\u1ec7 \u0103n th\u01b0\u1edfng l\u00e0 1:170 (Nh\u00e0 \u0111\u00e0i mi\u1ec1n B\u1eafc) v\u00e0 1:720 (Nh\u00e0 \u0111\u00e0i mi\u1ec1n Trung – Nam).<\/p>\n
C\u00f3 th\u1ec3 th\u1ea5y r\u1eb1ng h\u00ecnh th\u1ee9c \u0111\u00e1nh xi\u00ean 4 \u0111em t\u1edbi t\u1ef7 l\u1ec7 tr\u1ea3 th\u01b0\u1edfng c\u1ef1c cao. Tuy nhi\u00ean \u0111\u1ec3 chi\u1ebfn th\u1eafng \u1edf h\u00ecnh th\u1ee9c \u0111\u00e1nh xi\u00ean 4 th\u00ec kh\u00e1 kh\u00f3. Cho n\u00ean l\u00e0 ng\u01b0\u1eddi ch\u01a1i m\u1edbi khi ch\u01b0a c\u00f3 nhi\u1ec1u kinh nghi\u1ec7m th\u00ec b\u1ea1n kh\u00f4ng n\u00ean m\u1ea1o hi\u1ec3m \u0111\u1ec3 c\u01b0\u1ee3c cho xi\u00ean 4.<\/p>\n
C\u00e1ch \u0111\u00e1nh L\u00f4 xi\u00ean \u2013 l\u00f4 \u0111\u00e1 t\u1ea1i nh\u00e0 c\u00e1i Kubet<\/h2>\n
Hi\u1ec7n nay Kubet \u0111\u01b0\u1ee3c xem l\u00e0 nh\u00e0 c\u00e1i \u0111em l\u1ea1i 1 t\u1ef7 l\u1ec7 tr\u1ea3 th\u01b0\u1edfng kh\u00e1 cao cho ng\u01b0\u1eddi ch\u01a1i L\u00f4 xi\u00ean \u2013 l\u00f4 \u0111\u00e1. V\u00ec th\u1ebf ch\u01a1i L\u00f4 xi\u00ean Kubet \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi l\u1ef1a ch\u1ecdn. V\u1eady c\u00e1ch \u0111\u00e1nh L\u00f4 xi\u00ean \u2013 l\u00f4 \u0111\u00e1 t\u1ea1i Kubet nh\u01b0 th\u1ebf n\u00e0o?<\/p>\n
\u0110\u00e1nh L\u00f4 xi\u00ean \u2013 l\u00f4 \u0111\u00e1 Kubet tr\u00ean m\u00e1y t\u00ednh PC<\/h3>\n
Sau khi th\u00e0nh vi\u00ean \u0111\u0103ng nh\u1eadp v\u00e0o t\u00e0i kho\u1ea3n c\u00e1 c\u01b0\u1ee3c c\u1ee7a m\u00ecnh t\u1ea1i nh\u00e0 c\u00e1i Kubet. B\u1ea1n s\u1ebd n\u1ea1p ti\u1ec1n v\u00e0o t\u00e0i kho\u1ea3n Kubet \u0111\u1ec3 \u0111\u1ee7 \u0111i\u1ec1u ki\u1ec7n \u0111\u00e1nh L\u00f4 xi\u00ean \u2013 l\u00f4 \u0111\u00e1 nh\u01b0 sau:<\/p>\n